summaryrefslogtreecommitdiff
path: root/decoder/cfg.cc
diff options
context:
space:
mode:
Diffstat (limited to 'decoder/cfg.cc')
-rwxr-xr-xdecoder/cfg.cc143
1 files changed, 106 insertions, 37 deletions
diff --git a/decoder/cfg.cc b/decoder/cfg.cc
index a0c00e55..f51da9bf 100755
--- a/decoder/cfg.cc
+++ b/decoder/cfg.cc
@@ -10,7 +10,7 @@
#include "show.h"
#define DUNIQ(x) x
-#define DBIN(x)
+#define DBIN(x) x
#define DSP(x) x
//SP:binarize by splitting.
#define DCFG(x) IF_CFG_DEBUG(x)
@@ -262,9 +262,16 @@ struct add_virtual_rules {
set_nt_name(rhs);
}
inline void create_rule(Rhs const& rhs) {
- new_rules.push_back(CFG::Rule(newnt--,rhs));
+ new_rules.push_back(CFG::Rule(-newnt,rhs));
+ --newnt;
+ }
+ inline void create_adding(Rhs const& rhs) {
+ NTHandle nt=get_default(rhs2lhs,rhs,newnt);
+ assert(nt==newnt);
+ create(rhs);
}
inline void create(Rhs const& rhs) {
+ SHOWP(DSP,"Create ") SHOW3(DSP,newnt,newruleid,BinStr(rhs,nts,new_nts))
create_nt(rhs);
create_rule(rhs);
assert(newruleid==rules.size()+new_rules.size());assert(-newnt==nts.size()+new_nts.size());
@@ -291,76 +298,138 @@ struct add_virtual_rules {
}
//HACK: prevent this for instantiating for BinRhs. we need to use rule index because we'll be adding rules before we can update.
// returns 1 per replaced NT (0,1, or 2)
+ inline std::string Str(Rhs const& rhs) const {
+ return BinStr(rhs,nts,new_nts);
+ }
+
template <class RHSi>
int split_rhs(RHSi &rhs,bool only_free=false,bool only_reusing_1=false) {
+ typedef WordID const* WP;
//TODO: don't actually build substrings of rhs; define key type that stores ref to rhs in new_nts by index (because it may grow), and also allows an int* [b,e) range to serve as key (i.e. don't insert the latter type of key).
int n=rhs.size();
if (n<=2) return 0;
- int longest1=0;
+ int longest1=1;
int mid=n/2;
- int best_k=mid;
- bool haver,havel;
+ int best_k;
+ enum {HAVE_L=-1,HAVE_NONE=0,HAVE_R=1};
+ int have1=HAVE_NONE; // will mean we already have some >1 length prefix or suffix as a virt. (it's free). if we have both we use it immediately and return.
NTHandle ntr,ntl;
NTHandle bestntr,bestntl;
- WordID *b=&rhs.front(),*e=b+n;
+ WP b=&rhs.front(),e=b+n;
+ WP wk=b;
+ SHOWM3(DSP,"Split",Str(rhs),only_free,only_reusing_1);
+ int rlen=n;
for (int k=1;k<n-1;++k) {
//TODO: handle length 1 l and r parts without explicitly building Rhs?
- WordID *wk=&rhs[k];
+ ++wk; assert(k==wk-b);
+ --rlen; assert(rlen==n-k);
Rhs l(b,wk);
- int rlen=n-k;
if (have(l,ntl)) {
+ if (k>1) { SHOWM3(DSP,"Have l",k,n,Str(l)) }
Rhs r(wk,e);
if (have(r,ntr)) {
+ SHOWM3(DSP,"Have r too",k,n,Str(r))
rhs.resize(2);
rhs[0]=ntl;
rhs[1]=ntr;
return 2;
} else if (k>longest1) {
longest1=k;
- haver=false;
- havel=true;
+ have1=HAVE_L;
bestntl=ntl;
best_k=k;
}
- } else if (rlen>=longest1) {
+ } else if (rlen>longest1) { // > or >= favors l or r branching, maybe. who cares.
Rhs r(wk,e);
if (have(r,ntr)) {
longest1=rlen;
- havel=false;
- haver=true;
+ if (rlen>1) { SHOWM3(DSP,"Have r (only) ",k,n,Str(r)) }
+ have1=HAVE_R;
bestntr=ntr;
best_k=k;
}
}
+ //TODO: swap order of consideration (l first or r?) depending on pre/post midpoint? one will be useless to check for beating the longest single match so far. check that second
+
}
- bool no1=longest1<=1; // a single token sub-rhs part is not really interesting, but it would be reported as havel or haver.
+ // now we know how we're going to split the rule; what follows is just doing the actual splitting:
+
if (only_free) {
- if (no1) return 0;
- if (havel) {
- rhs.erase(rhs.begin()+1,rhs.begin()+best_k);
- rhs[0]=ntl;
- } else if (haver) {
- rhs.erase(rhs.begin()+best_k+1,rhs.end());
- rhs[best_k]=ntr;
+ if (have1==HAVE_NONE)
+ return 0;
+ if (have1==HAVE_L) {
+ rhs.erase(rhs.begin()+1,rhs.begin()+best_k); //erase [1..best_k)
+ rhs[0]=bestntl;
+ } else {
+ assert(have1==HAVE_R);
+ rhs.erase(rhs.begin()+best_k+1,rhs.end()); // erase (best_k..)
+ rhs[best_k]=bestntr;
}
return 1;
}
- if (only_reusing_1 && no1) return 0;
- //TODO: swap order of consideration (l first or r?) depending on pre/post midpoint? one will be useless to check for beating the longest single match so far. check that second.
- WordID *best_wk=b+best_k;
- Rhs l(b,best_wk);
- Rhs r(best_wk,e);
- //we build these first because adding rules may invalidate the underlying pointers (we end up binarizing already split virt rules)!
- rhs.resize(2);
- int nnt=newnt;
- rhs[0]=havel?bestntl:nnt--;
- rhs[1]=haver?bestntr:nnt;
- // now that we've set rhs, we can actually safely add rules
- if (!havel)
- create(l);
- if (!haver)
- create(r);
- return 2;
+ /* now we have to add some new virtual rules.
+ some awkward constraints:
+
+ 1. can't resize rhs until you save copy of l or r split portion
+
+ 2. can't create new rule until you finished modifying rhs (this is why we store newnt then create). due to vector push_back invalidation. perhaps we could bypass this by reserving sufficient space first before a splitting pass (# rules and nts created is <= 2 * # of rules being passed over)
+
+ */
+ if (have1==HAVE_NONE) { // default: split down middle.
+ DSP(assert(longest1==1));
+ WP m=b+mid;
+ if (n%2==0) {
+ WP i=b;
+ WP j=m;
+ for (;i!=m;++i,++j)
+ if (*i!=*j) goto notleqr;
+ // [...mid]==[mid...]!
+ RHS l(b,m); // 1. // this is equal to RHS(m,e).
+ rhs.resize(2);
+ rhs[0]=rhs[1]=newnt; //2.
+ create_adding(l);
+ return 1; // only had to create 1 total when splitting down middle when l==r
+ }
+ notleqr:
+ if (only_reusing_1) return 0;
+ best_k=mid; // rounds down
+ if (mid==1) {
+ RHS r(m,e); //1.
+ rhs.resize(2);
+ rhs[1]=newnt; //2.
+ create_adding(r);
+ return 1;
+ } else {
+ Rhs l(b,m);
+ Rhs r(m,e); // 1.
+ rhs.resize(2);
+ rhs[0]=newnt;
+ rhs[1]=newnt-1; // 2.
+ create_adding(l);
+ create_adding(r);
+ return 2;
+ }
+ }
+ WP best_wk=b+best_k;
+ //we build these first because adding rules may invalidate the underlying pointers (we end up binarizing already split virt rules)!.
+ //wow, that decision (not to use index into new_nts instead of pointer to rhs), while adding new nts to it really added some pain.
+ if (have1==HAVE_L) {
+ Rhs r(best_wk,e); //1.
+ rhs.resize(2);
+ rhs[0]=bestntl;
+ DSP(assert(best_wk<e-1)); // because we would have returned having both if rhs was singleton
+ rhs[1]=newnt; //2.
+ create_adding(r);
+ } else {
+ DSP(assert(have1==HAVE_R));
+ DSP(assert(best_wk>b+1)); // because we would have returned having both if lhs was singleton
+ Rhs l(b,best_wk); //1.
+ rhs.resize(2);
+ rhs[0]=newnt; //2.
+ rhs[1]=bestntr;
+ create_adding(l);
+ }
+ return 1;
}
};